(x-8)=(x^2+7x+12)

Solution for (x-8)=(x^2+7x+12) equation:

(x-8)=(x^2+7x+12)

We move all terms to the left:

(x-8)-((x^2+7x+12))=0

We get rid of parentheses

x-((x^2+7x+12))-8=0


We calculate terms in parentheses: -((x^2+7x+12)), so:

(x^2+7x+12)

We get rid of parentheses

x^2+7x+12

Back to the equation:

-(x^2+7x+12)


We get rid of parentheses

-x^2+x-7x-12-8=0

We add all the numbers together, and all the variables

-1x^2-6x-20=0

a = -1; b = -6; c = -20;
Δ = b2-4ac
Δ = -62-4·(-1)·(-20)
Δ = -44
Delta is less than zero, so there is no solution for the equation